Quality Inn Seymour I-65
12.6 miles away from Oak Meadow Apartments
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Quality Inn Seymour I-65 is a Quality hotel located at
2075 E Tipton St in Seymour, Indiana, approximately 12.6 miles
away from Oak Meadow Apartments (1450 Oak Meadows Drive).
The hotel has a 2.5-star rating. Check-in time is 3:00 PM. Check-out time is 11:00 AM.
The closest airport is Louisville International Airport,
approximately 53.8 miles from Quality Inn Seymour I-65.
More Hotels Near Oak Meadow Apartments
Quality Inn North Vernon near Hwy 50
2.1 miles
Make sure you read your reservation's cancellation policy. TheHotelNexus doesn't charge a cancellation fee, but many hotels do. The penalty can vary with the room rate that you choose - so read carefully!
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